Jefferson Township, Ashtabula County, Ohio
Jefferson Township, Ashtabula County, Ohio | |
|---|---|
Location of Jefferson Township in Ashtabula County | |
| Coordinates: 41°44′41″N 80°45′46″W / 41.74472°N 80.76278°W | |
| Country | United States |
| State | Ohio |
| County | Ashtabula |
| Area | |
• Total | 25.9 sq mi (67.0 km2) |
| • Land | 25.8 sq mi (66.7 km2) |
| • Water | 0.1 sq mi (0.3 km2) |
| Elevation | 906 ft (276 m) |
| Population (2020) | |
• Total | 5,317 |
| • Density | 204/sq mi (78.8/km2) |
| Time zone | UTC-5 (Eastern (EST)) |
| • Summer (DST) | UTC-4 (EDT) |
| ZIP code | 44047 |
| Area code | 440 |
| FIPS code | 39-38514 |
| GNIS feature ID | 1085729 |
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Jefferson Township is one of the twenty-seven townships of Ashtabula County, Ohio, United States. The population was 5,317 at the 2020 census.