Aubbeenaubbee Township, Fulton County, Indiana
Aubbeenaubbee Township | |
|---|---|
Location of Aubbeenaubbee Township in Fulton County | |
| Coordinates: 41°09′00″N 86°25′00″W / 41.15000°N 86.41667°W | |
| Country | United States |
| State | Indiana |
| County | Fulton |
| Government | |
| • Type | Indiana township |
| Area | |
• Total | 34.69 sq mi (89.8 km2) |
| • Land | 34.49 sq mi (89.3 km2) |
| • Water | 0.2 sq mi (0.5 km2) |
| Elevation | 741 ft (226 m) |
| Population (2020) | |
• Total | 1,346 |
| • Density | 42/sq mi (16/km2) |
| FIPS code | 18-02656 |
| GNIS feature ID | 453053 |
Aubbeenaubbee Township is one of eight townships in Fulton County, Indiana. As of the 2020 census, its population was 1,346 (down from 1,448 at 2010) and it contained 624 housing units.